# At the Wilmington Trust Bank, on average 6 customers

Question 1At the Wilmington Trust Bank, on average 6 customers arrive per hour at the drive-through window. What is the probability that, in any hour, less than 6 will arrive? Round your answer to 4 decimals.0.45300.44570.43350.4497Question 2Use this table for the following question.SupplierNumber ConformingNumber NonconformingA953B1266C552What is the probability of that a randomly selected part will be from supplier B, or a nonconforming unit from supplier A, or a conforming part from supplier C?0.70360.68460.66200.5761Question 3The number of cell phone minutes used by high school seniors during the school year follows a normal distribution with a mean of 487 and a standard deviation of 62. What is the probability that a student uses more than 410 minutes?0.59870.81330.81860.8925Question 4On the basis of past experience, 42% of the bills of a large mail-order book company are incorrect. If a random sample of five current bills is selected what is the probability that two or less are incorrect?0.64750.73540.87350.9730Question 5Ford Motor Company is confident that its 2016 F-150 truck gets 26 miles per gallon on the highway. Before they begin to advertise this fact they want to be 95% certain of their claim. To accomplish this, they take a random sample of 250 trucks and measure their gas mileage. The average was 24.98 mpg with a population standard deviation of 4.88 mpg. Calculate the Upper and Lower Confidence Interval values AND can Ford make the claim that their trucks will get 26 mpg on the highway.Lower = 23.95, Upper = 25.73 & Claim is no their trucks do not get 26 mpgLower = 24.38, Upper = 25.58 & Claim is no their trucks do not get 26 mpgLower = 24.21, Upper = 25.61, & Claim is no their trucks do not get 26 mpgLower = 24.19, Upper = 25.71, & Claim is no their trucks do not get 26 mpgQuestion 6The time required to complete a project is normally distributed with a mean of 112 weeks and a standard deviation of 14.35 weeks. The construction company must pay a penalty if the project is not finished by the due date in the contract. If a construction company bidding on this contract wishes to be 80 percent sure of finishing by the due date, what due date (project week #) should be negotiated?120.96124.08127.49130.39Question 7A local commuter bus service advertises that buses run every thirteen minutes along a certain route. What is the probability of a bus picking up the passengers at a given bus stop in less than or equal to 11 minutes following their arrival at the bus stop? (Hint: Use the exponential distribution method to solve this question)0.50360.57090.56540.5831Question 8The total expenses of a hospital are related to many factors. Two of these factors are the number of beds in the hospital, and the number of admissions. Data was collected on 8 hospitals as shown in the table below. Develop a regression model to predict the total expenses of a hospital based upon the number of beds.Expenses# Beds15921021293313159515426130516306952057471358885Y = 0.339x – 3.516Y = 0.339x – 4.171Y = 0.339x – 2.128 Y = 0.339x – 5.822Question 9The total expenses of a hospital are related to many factors. Two of these factors are the number of beds in the hospital, and the number of admissions. Data was collected on 8 hospitals as shown in the table below. Develop a regression model to predict the total expenses of a hospital based upon the number of admissions.ExpensesAdmissions157772127160315723042443514969315574553866Y = 0.671x + 9.284Y = 5.426 + 0.675xY = 0.671x + 3.931Y = 0.683x + 2.594Question 10The total expenses of a hospital are related to many factors. Two of these factors are the number of beds in the hospital, and the number of admissions. Data was collected on 8 hospitals as shown in the table below. Develop a regression model to predict the total expenses of a hospital based upon the number of beds and the number of admissions.Expenses# BedsAdmissions1572157721273361603157520230424135435143596932101557451405386906Y = 0.073X1 + 0.541X2 + 5.66Y = 0.073X1 +0.541X2 + 0.593Y = 0.028X1 + 0.631X2 + 1.56Y = 0.079X1 + 0.533X2 + 1.85Question 11Refer to the data and your solutions to questions 10 – 12 and identify which of the three models best predicts the expenses of a hospital. Note: use only the criteria mentioned in the four choices; do not go outside the problem to justify a choice.The regression model based upon beds only is the best because it has the highest r value.The regression model based upon admissions only is the best because it has the highest r value.The regression model based upon beds and admissions is the best because it has the highest r value.The regression model based upon beds only is the best because it has the highest r2 value.The regression model based upon admissions only is the best because it has the highest r2 value.Question 12Question 10 states: “The total expenses of a hospital are related to many factors. Two of these factors are the number of beds in the hospital, and the number of admissions.” Identify the F critical value for the regression model in Question 10.6.6085.7865.3184.459Question 13Scenario: The owner of the bike shop is concerned that his customer service is lacking and has decided to apply some statistical process control measures to his order fulfilling process so he contracted with a company specializing in gathering data on customer satisfaction. This organization tracked the number of order entry errors over a period of 25 days and in addition called 20 customers per day to and recorded the number of dissatisfied customer experiences. The table below is a record of the results from which you are to construct a p-Chart and a c-Chart for 95.5% confidence level.DayNo. Complaints# surveyedDayNo. Complaints# surveyed121514515241515415331516515461517615513151831568151921577152071584152151596152261510715235151171524015126152541513515Question 13: What is the p-chart Upper Control Limit for this scenario at the 95.5% level?0.41980.45860.55740.5924Question 14Refer to the data in the Question 13. What is the p-chart Lower Control Limit for this scenario at the 95.5% level?0.10090.10140.06540.0565Question 15Refer to the data in the Question 13. What is the c-chart Upper Control Limit for this scenario at the 95.5% level?10.3339.8189.7617.818Question 16Scenario: The data revealed that the most common complain was related to incorrect tire pressure in the front wheels of the mountain bike. Therefore each day, the Consultants randomly took 23 samples of five tire pressure reading which are shown in the table below and will be used to construct and x-bar and R charts. These data will be utilized for Questions 16 – 18.Question 16: What is the x-bar chart Upper Control Limit for this scenario at the 99.7% level?DaySample1Sample 2Sample 3Sample 4Sample 512026212528225292320233262131272742119222827519232930306283128212972825272130826232023259232526292110343334333411232327242912313030222013242727232814231921312315302328193116312520313117302332333318103223121919292922263020252829262521242429262422212319202823222926232830.99930.97130.77132.153Question 17Refer to the data in the Question 16. What is the x-bar chart Lower Control Limit for this scenario at the 99.7% level?20.58621.51620.06119.9334 points Question 18Refer to the data in Question 16. What is the R-bar chart Upper Limit for this scenario at the 99.7% level?18.66719.49520.04720.230Question 19If the arrival rate of customers entering into a system is 3 per hour (assume Poisson Distribution), the service rate is 6 per hour (assume exponential distribution) and there are 2 channels operating within the multichannel single-phase model, what is the probability of zero customers in the system?0.4290.5000.5560.600Question 20If the arrival rate of customers entering into a system is 4 per hour (assume Poisson Distribution), the service rate is 7 per hour (assume exponential distribution) and there are 3 channels operating within the multichannel single-phase model, what is the probability of zero customers in the system?0.6060.6510.5640.687Question 21If the arrival rate of customers entering into a system is 3 per hour (assume Poisson Distribution), the service rate is 4 per hour (assume exponential distribution) and there are 4 channels operating within the multichannel single-phase model, what is the probability of zero customers in the system?0.4720.6060.6520.670Question 22Scenario: A local bank is conducting a cost review of one of its drive-in window locations. Specially it wants to know the cost of manning its drive-in window operation using various numbers of customer service personnel to man its Multichannel, single-Phase system. Accountants have assembled the following data:Arrival Rate (assume Poisson distribution) per hour on average = 4 customersAverage Service Rate (assume exponential distribution) per channel per hour = 5 customersWait-time cost per hour = $56.00Teller Wages & Benefits per hour = $35.00Number of hours in operation per day = 8Question 22: What is the total daily cost (of the system) if one teller manned the drive-in window at this location?$2072.00$1412.00$1136.00$738.67Question 23Using the data from Question 22. What is the total daily cost (of the system) if two tellers manned the drive-in window at this location?$920.00$855.13$798.58$986.67Question 24Using the data from Question 22. What is the total daily cost (of the system) if three tellers manned the drive-in window at this location?$1206.88$1073.65$1193.20$1079.41Question 25Using the data from Question 22. If three tellers manned the drive-in window what is the utilization rate of its tellers?0.1900.2500.2670.222